200=45,522*x+2,529*x^2

Solution for 200=45,522*x+2,529*x^2 equation:

200=45.522x+2.529x^2

We move all terms to the left:

200-(45.522x+2.529x^2)=0

We get rid of parentheses

-2.529x^2-45.522x+200=0

a = -2.529; b = -45.522; c = +200;
Δ = b2-4ac
Δ = -45.5222-4·(-2.529)·200
Δ = 4095.452484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45.522)-\sqrt{4095.452484}}{2*-2.529}=\frac{45.522-\sqrt{4095.452484}}{-5.058}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45.522)+\sqrt{4095.452484}}{2*-2.529}=\frac{45.522+\sqrt{4095.452484}}{-5.058}
$